Hello Internet
<div class="IPBDescription">Do my assignments for me</div> Hey isn't it great, I have an extra credit assignment I don't understand and I'm sure you'll all be happy to help me.
<b>Determine your density</b>
And yes, I know that d = m/v and I know I can get my own mass, but aside from jumping in a tub I have no idea how to get my volume or density.
So help me.
<b>Determine your density</b>
And yes, I know that d = m/v and I know I can get my own mass, but aside from jumping in a tub I have no idea how to get my volume or density.
So help me.
Comments
Or just Google "average human density."
Weight is easy, however: Get on a scale, record weight
If all else fails, get a "cheat sheet" online, w/ the average weights, volumes, and body densities of your age group. (I dunno, google it)
Its not like they can check.
mark the line the water comes to, get out slowly so as not to carry much water out, then refill the tub with gallon jugs until it reaches the line? that could take too much water. so find a better way.
Or, for more accuracy, take your depth in segments, with each body part being a different depth. Arms, legs lower torso, upper torso, head, pelvis should be good enough.
Or, for more accuracy, take your depth in segments, with each body part being a different depth. Arms, legs lower torso, upper torso, head, pelvis should be good enough. <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
And then for added fun put some bullet casings and blood along the outline.
Or, for more accuracy, take your depth in segments, with each body part being a different depth. Arms, legs lower torso, upper torso, head, pelvis should be good enough. <!--QuoteEnd--></td></tr></table><div class='postcolor'><!--QuoteEEnd-->
And then for added fun put some bullet casings and blood along the outline. <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
And do not cross tape.
Weight is easy, however: Get on a scale, record weight
If all else fails, get a "cheat sheet" online, w/ the average weights, volumes, and body densities of your age group. (I dunno, google it) <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
Mass != Weight. Mss is the amount of matter you have, weight is the gravitational force that is exerted on that mass. For example, something on the moon has less weight then the same thing on Earth, but it has the same mass.
You could put water in a tub, mark the line, get in, mark a new line, then get out. Find the area by multiplying L x W x H (assuming a rectangular tub). It sounds simple enough, though if it were me, I wouldn't bother with doing it (since it is extra credit and actually involves some effort).
Or, for more accuracy, take your depth in segments, with each body part being a different depth. Arms, legs lower torso, upper torso, head, pelvis should be good enough. <!--QuoteEnd--></td></tr></table><div class='postcolor'><!--QuoteEEnd-->
And then for added fun put some bullet casings and blood along the outline. <!--QuoteEnd--></td></tr></table><div class='postcolor'><!--QuoteEEnd-->
And do not cross tape. <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
Or cut out all this dang work and just shoot a hobo.
that is it.
simple aint it?
that is it.
simple aint it? <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
I think making it up would be simpler. Here, let me help you:
45.32kg/m
1. Obtain hamster.
2. Measure volume of common drink mug.
3. Completely fill with water.
4. Completely dunk hamster.
5. Remove hamster.
6. Measure volume lost.
etc.
2+2= dumbell
so I say my "density" is dumbell. <!--emo&:p--><img src='http://www.unknownworlds.com/forums/html//emoticons/tounge.gif' border='0' style='vertical-align:middle' alt='tounge.gif' /><!--endemo-->
You could put water in a tub, mark the line, get in, mark a new line, then get out. Find the area by multiplying L x W x H (assuming a rectangular tub). It sounds simple enough, though if it were me, I wouldn't bother with doing it (since it is extra credit and actually involves some effort). <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
Most tubs are NOT rectangular tho... the one end is a 45* slope, the corners are rounded, AND the tub itself is at aroudn a 5* slope... so you'd have a fair margin of error there...
best thing I can think of would be to buy a PARABOLIC swimming pool (one of those little kiddy pools... make sure it has at LEAST 2 foot high sides) and fill it all of the way up. Then, just SLOWLY get in. COMPLETELY submerge yourself. Then, get out SLOWLY. Use a 5 gallon and a 1 gallon container to see how many gallons you misplaced. then, calculate the area of the water (find a box, fill it with ONE gallon of water, and find the area of the dimensions)
SHOULD work... but it's NOT gonna be a pretty equation... and it'll take the better part of an afternoon...
V1/V2 = D2/D1
where V1 is the volume of the water <b>displaced by your body</b>, V2 is the volume of water, D2 is the density of your body, and D1 is the density of water
(1000 kg/m^3).
First though, you need the volume of water in the tub. So measure the height of the water and take the dimensions of the length and width of the tub. That should get you your V2.
A really clever way to do this is to use the suggestion given before: mark the height of the water in the tub <b>without you in it </b>and then jump in and mark the height of the water in the tub with you in it. now take this difference (h = new height - original height) and put it into the volume formula for a rectangle (V1 = l x w x h) to get the volume of water displaced by you, where l and w are the length and width of the tub respectively.
So now you should be able to determine your body's density by substitution: D2=(V1xD1)/V2.
To get the actual volume of your body, take the density you found of yourself, and, knowing your mass (in kilograms), substitute the numbers into D=M/V to get it.
Now its not precise because a bath tub is not a perfect rectangle, the answer you get won't be exact but will be a good approximation.
V1/V2 = D2/D1
where V1 is the volume of the water <b>displaced by your body</b>, V2 is the volume of water, D2 is the density of your body, and D1 is the density of water
(1000 kg/m^3).
First though, you need the volume of water in the tub. So measure the height of the water and take the dimensions of the length and width of the tub. That should get you your V2.
A really clever way to do this is to use the suggestion given before: mark the height of the water in the tub <b>without you in it </b>and then jump in and mark the height of the water in the tub with you in it. now take this difference (h = new height - original height) and put it into the volume formula for a rectangle (V1 = l x w x h) to get the volume of water displaced by you, where l and w are the length and width of the tub respectively.
So now you should be able to determine your body's density by substitution: D2=(V1xD1)/V2.
To get the actual volume of your body, take the density you found of yourself, and, knowing your mass (in kilograms), substitute the numbers into D=M/V to get it.
Now its not precise because a bath tub is not a perfect rectangle, the answer you get won't be exact but will be a good approximation. <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
physics problem = owned