Conics Suck.

LegionnairedLegionnaired Join Date: 2002-04-30 Member: 552Members, Constellation
in Off-Topic
I have to turn (x-h)^2=4p(y-k) into y=a(x-h)^2+k. Normally it'd be easy, but i seem to have forgotten what the proof is to turn 1/4p into a. If someone could help, I'd appriciate it.
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Comments

  • Nemesis_ZeroNemesis_Zero Old European Join Date: 2002-01-25 Member: 75Members, Retired Developer, NS1 Playtester, Constellation
    My fathers girlfriend, who used to study maths, took a stab at it: All you have to do is exchange the (x-h)² in the second equation by 4p(y-k), which is how it is defined by the first equation. Now solve the result after y, et voilá...
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  • LegionnairedLegionnaired Join Date: 2002-04-30 Member: 552Members, Constellation
    Thanks, that's exactly what I needed!
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  • Nil_IQNil_IQ Join Date: 2003-04-15 Member: 15520Members
    Ummmm, what level maths is that??? I'm doing AS level Maths and plan to go on to do the A2, and looking at that scares the crap out of me!

    (is crap on the swear filter?)
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  • SaltySalty Join Date: 2002-11-05 Member: 6970Members
    edited May 2003
    I think you start conic sections in Algebra 2.

    I would do it by
    (x-h)^2 = 4p(y-k)
    (x-h)^2/4p = (y-k)
    1/4p*(x-h)^2 + k = y = a(t-h)^2 + k
    a= 1/4p
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  • OttoDestructOttoDestruct Join Date: 2002-11-08 Member: 7790Members
    That stuff is simple... all you do is substitute then its simple algebra from there
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  • ConfuzorConfuzor Join Date: 2002-11-01 Member: 2412Awaiting Authorization
    <!--QuoteBegin--Nil_IQ+May 29 2003, 01:21 PM--></span><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (Nil_IQ @ May 29 2003, 01:21 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> Ummmm, what level maths is that??? I'm doing AS level Maths and plan to go on to do the A2, and looking at that scares the crap out of me!

    (is crap on the swear filter?) <!--QuoteEnd--> </td></tr></table><span class='postcolor'> <!--QuoteEEnd-->
    I think it's just a different notation of doing the work. What are those equations relating to? Hyperbolas?
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  • SaltySalty Join Date: 2002-11-05 Member: 6970Members
    edited May 2003
    Parabolas.

    Hyperbolas are like: (x^2)-h/(a^2) - (y^2)-k/(b^2) = 0 or something like that. <!--emo&;)--><img src='http://www.unknownworlds.com/forums/html/emoticons/wink.gif' border='0' style='vertical-align:middle' alt='wink.gif'><!--endemo-->
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  • NumbersNotFoundNumbersNotFound Join Date: 2002-11-07 Member: 7556Members
    edited May 2003
    <!--QuoteBegin--Salty+May 29 2003, 08:19 PM--></span><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (Salty @ May 29 2003, 08:19 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> Parabolas.

    Hyperbolas are like:  (x^2)/a^2 - (y^2)/b^2 = 0 or something like that.  <!--emo&;)--><img src='http://www.unknownworlds.com/forums/html/emoticons/wink.gif' border='0' style='vertical-align:middle' alt='wink.gif'><!--endemo--> <!--QuoteEnd--></td></tr></table><span class='postcolor'><!--QuoteEEnd-->
    Hmmm.... isn't that a degenerate hyperbola? I think they have to equal 1... or maybe that's for an ellipse.


    Actually, it's ((x-h)^2/(a^2))-((y-k)^2/(b^2))=1, if it has a horizontal transverse axis, the numerators are switched if it's vertical.


    I have a test on this tomorrow and it's the last test of the year <!--emo&:)--><img src='http://www.unknownworlds.com/forums/html/emoticons/smile.gif' border='0' style='vertical-align:middle' alt='smile.gif'><!--endemo--> I think it's pretty easy stuff.
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  • SaltySalty Join Date: 2002-11-05 Member: 6970Members
    edited May 2003
    I havent had them in a while so your prolly right. I just know thats a parabola though.
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  • FamFam Diaper-Wearing Dog On A Ball Join Date: 2002-02-17 Member: 222Members, NS1 Playtester, Contributor
    <!--QuoteBegin--Nil_IQ+May 29 2003, 10:21 PM--></span><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (Nil_IQ @ May 29 2003, 10:21 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> Ummmm, what level maths is that??? I'm doing AS level Maths and plan to go on to do the A2, and looking at that scares the crap out of me! <!--QuoteEnd--> </td></tr></table><span class='postcolor'> <!--QuoteEEnd-->
    Don't worry, Conics are not on the AS or A2 syllabuses. Unless you go on to do degree level maths, you'll be fine in this respect. However, you <b>are</b> doing A2 Maths, and so I pity you anyhow. <!--emo&:p--><img src='http://www.unknownworlds.com/forums/html/emoticons/tounge.gif' border='0' style='vertical-align:middle' alt='tounge.gif'><!--endemo-->
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  • GlissGliss Join Date: 2003-03-23 Member: 14800Members, Constellation, NS2 Map Tester
    Yeah, I'm about 4 years behind this, maybe more.

    Although, those are a lot of numbers! Graah!
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  • TalesinTalesin Our own little well of hate Join Date: 2002-11-08 Member: 7710NS1 Playtester, Forum Moderators
    It's funny... I've completed all the specialized requirements for a programming AS (or BS if I transferred and took one more class... err.. and all my Cores) but all of that goes painfully over my head. So I'll shunt it off to the side and think of puppies, which do not involve math on anything more than a very abstract level which would only be invoked by niggling micro-detail perfectionists, or in some cases dog ranches... though their calculations usually run closer to 1+1=3-8.
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  • BurrBurr Join Date: 2002-11-19 Member: 9358Members
    Im finally out of the math classes, sure I still use it, but its not a primary thing to learn anymore!!

    5 qrtrs of calculus is enough......

    the derivative (hereby known as d):

    dx^2 = 2x


    thats about all I care to remember, and that sin ans cos are reversed, and the inegral (i think its the integral) of e^x is e^x
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  • Nemesis_ZeroNemesis_Zero Old European Join Date: 2002-01-25 Member: 75Members, Retired Developer, NS1 Playtester, Constellation
    The equation at hand was really not too difficult. Maybe I'll post some of my latest tests to compare <!--emo&:)--><img src='http://www.unknownworlds.com/forums/html/emoticons/smile.gif' border='0' style='vertical-align:middle' alt='smile.gif'><!--endemo-->
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  • LegionnairedLegionnaired Join Date: 2002-04-30 Member: 552Members, Constellation
    edited May 2003
    Yeah, nem answered this straight off, I forgot about substituting the (x - h)^2 term.

    Oh, and for all you scared by this stuff:

    f(x) = 4x^2+x+3

    Find the line tangent to the equation that intersects the graph at x = 4 <!--emo&:)--><img src='http://www.unknownworlds.com/forums/html/emoticons/smile.gif' border='0' style='vertical-align:middle' alt='smile.gif'><!--endemo--> .

    EDIT Answer:

    f'(x) = 8x +1
    f'(4) = 32 +1
    m = 33

    f(4) = 64+4+3
    f(4) = 71

    33(x - 4) = (y-71)
    33x - 132 = y - 71

    y = 33x - 61 is the tangent line <!--emo&:)--><img src='http://www.unknownworlds.com/forums/html/emoticons/smile.gif' border='0' style='vertical-align:middle' alt='smile.gif'><!--endemo-->
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  • Nemesis_ZeroNemesis_Zero Old European Join Date: 2002-01-25 Member: 75Members, Retired Developer, NS1 Playtester, Constellation
    edited May 2003
    Finally found a site with examples for the kind of stuff I had to do for the last two years. This is a rather basic task:

    The graph of f(x)=1/12x³(x-4) and y=0 enclose an area. How big is this area?

    [edit]Hints:

    f(x) and y=0 intersect at N1(0|0), because 1/12*0³=0; and N2(4|0), because (4-4)=0. Thus, the area is limited by x1=0 and x2=4.

    Now get F(x) and integrate the whole mess.[/edit]
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  • LegionnairedLegionnaired Join Date: 2002-04-30 Member: 552Members, Constellation
    That's the kind of stuff I'll be doing next year, it looks massively cool.
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  • Nemesis_ZeroNemesis_Zero Old European Join Date: 2002-01-25 Member: 75Members, Retired Developer, NS1 Playtester, Constellation
    I can assure you it's not.
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  • sekdarsekdar Join Date: 2002-11-21 Member: 9564Members
    calculus. ugh. so glad i got that over with while i'm still in HS.
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  • X_StickmanX_Stickman Not good enough for a custom title. Join Date: 2003-04-15 Member: 15533Members, Constellation
    í. hate. maths. Especialy algebra. Numbers is numbers and letters is letters. shudnt be mixed. werd
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  • Error404Error404 Join Date: 2002-11-19 Member: 9353Members
    I stick to art. I suck at maths.
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  • NumbersNotFoundNumbersNotFound Join Date: 2002-11-07 Member: 7556Members
    Just took my last pre-calc test... on conics...

    Hope i do well on it!
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