Maths thing for all you maths heads
Mouse
The Lighter Side of Pessimism Join Date: 2002-03-02 Member: 263Members, NS1 Playtester, Forum Moderators, Squad Five Blue, Reinforced - Shadow, WC 2013 - Shadow
The Lighter Side of Pessimism Join Date: 2002-03-02 Member: 263Members, NS1 Playtester, Forum Moderators, Squad Five Blue, Reinforced - Shadow, WC 2013 - Shadow
in Off-Topic
<div class="IPBDescription">No fun whatsoever</div>ok people this is a formula i worked out. try it
a= odd number bigger than 1
(a-1)÷2=y
a×y+y=b
b+1=c
a²+b²=c²
ok if you didn't guess already. this formula works with pythagoras theorem. what it does is finds triads comprised of only whole numbers, eg. 3,4,5 or 5,12,13. and that aren't doubles of other triads like 6,8,10
and by the way this formula is mine all mine mwahahaha <!--emo&:p--><img src="http://www.natural-selection.org/iB_html/non-cgi/emoticons/tounge.gif" border="0" valign="absmiddle" alt=':p'><!--endemo-->
in other words don't claim it as your own or something
a= odd number bigger than 1
(a-1)÷2=y
a×y+y=b
b+1=c
a²+b²=c²
ok if you didn't guess already. this formula works with pythagoras theorem. what it does is finds triads comprised of only whole numbers, eg. 3,4,5 or 5,12,13. and that aren't doubles of other triads like 6,8,10
and by the way this formula is mine all mine mwahahaha <!--emo&:p--><img src="http://www.natural-selection.org/iB_html/non-cgi/emoticons/tounge.gif" border="0" valign="absmiddle" alt=':p'><!--endemo-->
in other words don't claim it as your own or something
Comments
<!--c1--></span><table border="0" align="center" width="95%" cellpadding="3" cellspacing="1"><tr><td><b>Code Sample</b> </td></tr><tr><td id="CODE"><!--ec1-->a=2y+1 b=ay+y ==> b=2y^2+2y
c=b+1 ==> c=2y^2+2y+1
a^2=4y^2+4y+1 b^2=4y^4+8y^3+4y^2
a^2+b^2=4y^4+8y^3+8y^2+4y+1
c^2=4y^4+4y^3+2y^2+4y^3+4y^2+2y+2y^2+2y+1=4y^4+8y^3+8y^2+4y+1
a^2+b^2=c^2<!--c2--></td></tr></table><span id='postcolor'><!--ec2-->
So yeah, it works. Pretty cool.
For instance, if a=3.15 (still an odd number), then your formula ends up trying to equate 37.315 to 39.69.
Kheldar: yes, but i'm only 15
Greedo: <blink> blink> umm yes, what is that? <!--emo&???--><img src="http://www.natural-selection.org/iB_html/non-cgi/emoticons/confused.gif" border="0" valign="absmiddle" alt='???'><!--endemo-->
8456743/
never mind i cant find squre root symbol so you win
Given 2 equal numbers, s and t:
s = t Given.
s*t = t*t Multiply by t.
s*t = t^2 Just a simplification.
s*t - s^2 = t^2 - s^2 Subtract s^2 from both sides.
s(t - s) = (t + s)(t - s) Factor out (t-s) from both sides, and then divide to remove from equation.
s = t + s This is what you get.
s = s + s Substitute s for t.
s = 2s Simplify.
1 = 2 Divide by s.
There ya go. Now tell me what's wrong.
So if you think of 'undefined' as infinity, then:
1(infinity) = 2(infinity)
or
1(0) = 2(0)
I personally believe you CAN divide by zero.
<!--EDIT|Greedo386|April 18 2002,18:31-->
s = s + s Substitute s for t.
s = 2s Simplify.
1 = 2 Divide by s.
There ya go. Now tell me what's wrong.<!--QuoteEnd--></td></tr></table><span id='postcolor'><!--QuoteEEnd-->
The bold line is where the problem lies. The equation isn't balanced yet. s=t+s works out to be t=0 (since s-s=t), so substituting s for t in the next line essentially gives you: 0=0+0
I did it too. It actually works for integers...
My favorite gag, well, I two...
.9 reccuring = 1
I have 11 fingers (no deformites...)
They're both flaws in math, but its fun watching big math types go into fights trying to disprove it.